SQL Left Outer Join Tutorial with Example: Employee Bonus
- 时间:2020-10-05 13:15:44
- 分类:网络文摘
- 阅读:119 次
SQL Left Outer Join can be illustrated by the following:

sql-left-outer-join
where the query will take everything from left table and those fields from the right table. Let’s take a look at the following question as a left-outer-join (which is known as left-join) example.
Employee Bonus
Select all employee’s name and bonuses whose bonus is less than $1000.
SQL Schema
Create table If Not Exists Employee (EmpId int, Name varchar(255), Supervisor int, Salary int)
Create table If Not Exists Bonus (EmpId int, Bonus int)
Truncate table Employee
insert into Employee (EmpId, Name, Supervisor, Salary) values ('3', 'Brad', 'None', '4000')
insert into Employee (EmpId, Name, Supervisor, Salary) values ('1', 'John', '3', '1000')
insert into Employee (EmpId, Name, Supervisor, Salary) values ('2', 'Dan', '3', '2000')
insert into Employee (EmpId, Name, Supervisor, Salary) values ('4', 'Thomas', '3', '4000')
Truncate table Bonus
insert into Bonus (EmpId, Bonus) values ('2', '500')
insert into Bonus (EmpId, Bonus) values ('4', '2000')
Table:Employee
+-------+--------+-----------+--------+ | empId | name | supervisor| salary | +-------+--------+-----------+--------+ | 1 | John | 3 | 1000 | | 2 | Dan | 3 | 2000 | | 3 | Brad | null | 4000 | | 4 | Thomas | 3 | 4000 | +-------+--------+-----------+--------+empId is the primary key column for this table.
Table: Bonus
+-------+-------+ | empId | bonus | +-------+-------+ | 2 | 500 | | 4 | 2000 | +-------+-------+empId is the primary key column for this table.
Example ouput:
+-------+-------+ | name | bonus | +-------+-------+ | John | null | | Dan | 500 | | Brad | null | +-------+-------+
The SQL of left-join will return all the employees and their bonuses, however, some employees don’t have bonuses – as they are not shown in the Bonus table. Therefore, the result field (bonus) will be empty for those employees. Thus, we have to explicitly use IS (or IS NOT) operator to check for nullness.
SELECT
Employee.name, Bonus.bonus
FROM
Employee
LEFT JOIN
Bonus ON Employee.empid = Bonus.empid
WHERE
bonus < 1000 OR bonus IS NULL;
–EOF (The Ultimate Computing & Technology Blog) —
推荐阅读:演艺明星代言问题食品要依法追责 危害食品安全的犯罪手段更趋隐蔽 对危害食品安全犯罪案件从严量刑 媒体评论:食品安全乱象,谁之过? 健康饮食:妙用瓜果防治夏季疾病 农夫山泉危机曝出饮用水行业乱象 消费者严重不信任国产奶粉的原因 国人消费崇洋媚外导致洋奶粉的傲慢 暴利诱惑导致贴牌洋奶粉占八成市场 食药监部门曝光12个保健食品违法广告
- 评论列表
-
- 添加评论