SQL Left Outer Join Tutorial with Example: Employee Bonus

  • 时间:2020-10-05 13:15:44
  • 分类:网络文摘
  • 阅读:136 次

SQL Left Outer Join can be illustrated by the following:

sql-left-outer-join SQL Left Outer Join Tutorial with Example:  Employee Bonus database mysql sql

sql-left-outer-join

where the query will take everything from left table and those fields from the right table. Let’s take a look at the following question as a left-outer-join (which is known as left-join) example.

Employee Bonus

Select all employee’s name and bonuses whose bonus is less than $1000.

SQL Schema

Create table If Not Exists Employee (EmpId int, Name varchar(255), Supervisor int, Salary int)
Create table If Not Exists Bonus (EmpId int, Bonus int)
Truncate table Employee
insert into Employee (EmpId, Name, Supervisor, Salary) values ('3', 'Brad', 'None', '4000')
insert into Employee (EmpId, Name, Supervisor, Salary) values ('1', 'John', '3', '1000')
insert into Employee (EmpId, Name, Supervisor, Salary) values ('2', 'Dan', '3', '2000')
insert into Employee (EmpId, Name, Supervisor, Salary) values ('4', 'Thomas', '3', '4000')
Truncate table Bonus
insert into Bonus (EmpId, Bonus) values ('2', '500')
insert into Bonus (EmpId, Bonus) values ('4', '2000')

Table:Employee

+-------+--------+-----------+--------+
| empId |  name  | supervisor| salary |
+-------+--------+-----------+--------+
|   1   | John   |  3        | 1000   |
|   2   | Dan    |  3        | 2000   |
|   3   | Brad   |  null     | 4000   |
|   4   | Thomas |  3        | 4000   |
+-------+--------+-----------+--------+

empId is the primary key column for this table.

Table: Bonus

+-------+-------+
| empId | bonus |
+-------+-------+
| 2     | 500   |
| 4     | 2000  |
+-------+-------+

empId is the primary key column for this table.

Example ouput:

+-------+-------+
| name  | bonus |
+-------+-------+
| John  | null  |
| Dan   | 500   |
| Brad  | null  |
+-------+-------+

The SQL of left-join will return all the employees and their bonuses, however, some employees don’t have bonuses – as they are not shown in the Bonus table. Therefore, the result field (bonus) will be empty for those employees. Thus, we have to explicitly use IS (or IS NOT) operator to check for nullness.

SELECT
    Employee.name, Bonus.bonus
FROM
    Employee
LEFT JOIN
    Bonus ON Employee.empid = Bonus.empid
WHERE
    bonus < 1000 OR bonus IS NULL;

–EOF (The Ultimate Computing & Technology Blog) —

推荐阅读:
Recursive Depth First Search Algorithm to Compute the Sum of Nod  How to Convert Integer to the Sum of Two No-Zero Integers?  Algorithm to Generate the Spiral Matrix in Clock-wise Order  How to Remove the Duplicates from Sorted List (Leaving Only Dist  How to Sort a Linked List by Converting to Array/Vector?  Know The Effective and Smart SEO Reporting Tool You Must Use  Pro Content Marketing Tips You Can Implement NOW  8 WordPress Plugins for Better User Experience  6 Eye-Opening Tips for Measuring and Improving the Impact of You  Should a Professional Blog Be Funny? 
评论列表
添加评论