Power Digit Sum: What is the sum of the digits of the number 2^1
- 时间:2020-09-10 12:45:51
- 分类:网络文摘
- 阅读:148 次
215 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 21000?
You probably can compute the direct value of 2^1000. For example, in Python, you can obtain value of (2**1000) and convert it to string. In Java, you can use BigInteger to compute the value of two to the power of 1000.
We can use an array, or hash map to store the digits of any big number. Each time we multiple each position (the values) of the array/hashmap by two, then we need to start from the ‘One’ position to carry over the digits.
The following Javascript code first computes the value of 21000 (values store in a dictionary), then compute the sum of all the digits using reduce() method.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | let arr = { 0: 1 }; for (let i = 1; i <= 1000; ++i) { // multiple each digit by two Object.keys(arr).map(x => { arr[x] *= 2; }); let c = Math.floor(arr[0] / 10); let j = 1; arr[0] %= 10; // highest position const maxKey = Math.max(...Object.keys(arr)); while ((c > 0) || (j <= maxKey)) { if (typeof arr[j] === 'undefined') { arr[j] = c; } else { arr[j] = arr[j] + c; } c = Math.floor(arr[j] / 10); arr[j] %= 10; j ++; } } // sum up all the digits console.log(Object.values(arr).reduce((a, b) => a + b)); |
let arr = {
0: 1
};
for (let i = 1; i <= 1000; ++i) {
// multiple each digit by two
Object.keys(arr).map(x => {
arr[x] *= 2;
});
let c = Math.floor(arr[0] / 10);
let j = 1;
arr[0] %= 10;
// highest position
const maxKey = Math.max(...Object.keys(arr));
while ((c > 0) || (j <= maxKey)) {
if (typeof arr[j] === 'undefined') {
arr[j] = c;
} else {
arr[j] = arr[j] + c;
}
c = Math.floor(arr[j] / 10);
arr[j] %= 10;
j ++;
}
}
// sum up all the digits
console.log(Object.values(arr).reduce((a, b) => a + b));The answer is 1366.
Based on the same algorithm, we can solve another math puzzle: Compute Factorial Digit Sum: Find the sum of the digits in the number 100!
–EOF (The Ultimate Computing & Technology Blog) —
推荐阅读:辽宁体育直播-辽宁体育在线直播观看「高清」 北京体育频道直播-北京体育在线直播观看「高清」 五星体育直播-五星体育在线直播观看「高清」 风云足球直播-风云足球在线直播观看「高清」 吉林篮球直播-吉林篮球在线直播观看「高清」 江苏体育直播-江苏体育在线直播观看「高清」 广州竞赛直播-广州竞赛频道在线直播观看「高清」 广东体育频道直播-广东体育频道在线直播观看「高清」 高尔夫网球频道直播-CCTV高尔夫网球在线直播「高清」 央视台球频道直播-斯诺克直播「高清」
- 评论列表
-
- 添加评论