数学题：玉龙粮食加工厂生产一批面粉，分三次运出，

第一次运出的比总数的四分之一还多一百袋，

第二次运出的是第一次的四分之三，

第三次运出九十五袋，

这批面粉共有多少袋？求解。

数学题解答：

等量关系:总量-三次运出的数量=0

解:设这批面粉共有x袋。

由题得：x-(1/4x+100)-3/4(1/4x+100)-95=0

解得：x=480

答:这批面粉共有480袋。

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