巧用份数解决问题
- 时间:2020-03-30 19:01:27
- 分类:数学世界
- 阅读:172 次
有甲、乙、丙三个车间,他们的工人总数少于1000人。其中女工人数是男工的43%,已知甲车间比乙车间多38人,丙车间比甲车间多70人。三个车间的总人数是多少?(六年级)
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这道题中仅仅给出了工人总数的大致范围是少于1000人,其中“女工人数是男工人数的43%”是一条重要信息,这条信息透露出女工与男工人数的份数。具体 解答思路如下:
男女工总份数是:43+100=143份,1000以内143的倍数有:143*1,143*2,……143*6共6种结果。乙车间人最少,甲比乙多38,丙比乙多70+38,两者共多出146人。从总人数中去掉146后,就是乙车间人数的3倍。将以上六种可能的结果,逐一减去146后,看是不是3的倍数即可,最后答案为572人。
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