Bruteforce Algorithm to Compute the Maxmium Powerful Digit Sum u

  • 时间:2020-09-09 13:16:32
  • 分类:网络文摘
  • 阅读:123 次

A googol (10100) is a massive number: one followed by one-hundred zeros; 100100 is almost unimaginably large: one followed by two-hundred zeros. Despite their size, the sum of the digits in each number is only 1.

Considering natural numbers of the form, ab, where a, b < 100, what is the maximum digital sum?

Maxmium Powerful Digit Sum using Java’s BigInteger

Given a and b are in short range of [0 to 99]. There bruteforce algorithm should be more than enough to solve the problem. We need to check total 100*100 different combinations of a to the power b.

In order to hold such large number, we can use array, or in Java, we can simply use the java.math.BigInteger. See below Java’s trivial implementation using the BigInteger. The result (BigInteger) is converted to String type, then the digits are sum, then updating the maximum.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
package com.helloacm;
 
import lombok.var;
import java.math.BigInteger;
 
public class Main {
    public static void main(String[] args) {
        int ans = 0;
        for (var a = 2; a < 100; ++ a) {
            for (var b = 2; b < 100; ++ b) {
                var c = BigInteger.valueOf(a).pow(b);
                var v = c.toString();
                var sum = 0;
                for (var x: v.toCharArray()) {
                    sum += x - 48;
                    ans = Math.max(sum, ans);
                }
            }
        }
        System.out.println(ans);
    }
}
package com.helloacm;

import lombok.var;
import java.math.BigInteger;

public class Main {
    public static void main(String[] args) {
        int ans = 0;
        for (var a = 2; a < 100; ++ a) {
            for (var b = 2; b < 100; ++ b) {
                var c = BigInteger.valueOf(a).pow(b);
                var v = c.toString();
                var sum = 0;
                for (var x: v.toCharArray()) {
                    sum += x - 48;
                    ans = Math.max(sum, ans);
                }
            }
        }
        System.out.println(ans);
    }
}

The answer is 972.

–EOF (The Ultimate Computing & Technology Blog) —

推荐阅读:
How to Iterate over the Items in Java’s Map (HashMap, Hash  Dynamic Programming Algorithm to Count Vowels Permutation  Exploring the Importance of Brand Consistency  Cleaning A WordPress Malware Infection For Dummies  7 Killer Ways to Higher Average Time on Page  6 Tips for Creating Infographics to Make Your Blog Stand Out  11 Foolproof Hacks to Drive Traffic to Your Blog in 2019  7 Things Gutenberg Block Editor Does Better Than The Classic Edi  Top 6 Things to Keep in Mind While Sending Bulk Emails  7 Tweaks to Amplify Your Landing Page’s Conversion Rate 
评论列表
添加评论