数学题:何时换轮胎
- 时间:2020-05-12 13:42:36
- 分类:数学世界
- 阅读:125 次
数学题:何时换轮胎?自行车前轮轮胎寿命5000千米,后轮轮胎寿命3000千米,如果中间将两个轮胎调换一下,使两个轮胎同时坏,请问:何时换?两个轮胎都坏时,自行车最多行多少千米?
数学题解答:用方程解答试试。
设在x千米时换。
(1 – x/5000)÷(1/3000)=(1-x/3000)÷(1/5000)
解这个方程,得x=1875。
答:在行驶了1875千米时更换前后轮胎。
(1 – 1875/5000)÷(1/3000)+1875=3750(千米)
答:自行车最多行3750千米。
推荐阅读:Smallest Multiple Algorithm using Bruteforce or GCD/LCM How many different ways can £2 be made using any number of coins Compute Factorial Digit Sum: Find the sum of the digits in the n Compute the Maximum Integer Right Triangles Solutions Power Digit Sum: What is the sum of the digits of the number 2^1 Digit factorials: Find the Sum of All the Curious Numbers Computing the Longest Recurring Cycle in its Decimal Fraction Pa How to Use Priority Queue in Java or C++ to Compute Last Stone W 5 Most Important SEO Keyword Metrics, Explained Why You Should Remove Inactive Subscribers from Your Email List
- 评论列表
-
- 添加评论