数学题:何时换轮胎

  • 时间:2020-05-12 13:42:36
  • 分类:数学世界
  • 阅读:125 次

数学题:何时换轮胎?自行车前轮轮胎寿命5000千米,后轮轮胎寿命3000千米,如果中间将两个轮胎调换一下,使两个轮胎同时坏,请问:何时换?两个轮胎都坏时,自行车最多行多少千米?

数学题解答:用方程解答试试。

设在x千米时换。

(1 – x/5000)÷(1/3000)=(1-x/3000)÷(1/5000)

解这个方程,得x=1875。

答:在行驶了1875千米时更换前后轮胎。

(1 – 1875/5000)÷(1/3000)+1875=3750(千米)

答:自行车最多行3750千米。

推荐阅读:
Smallest Multiple Algorithm using Bruteforce or GCD/LCM  How many different ways can £2 be made using any number of coins  Compute Factorial Digit Sum: Find the sum of the digits in the n  Compute the Maximum Integer Right Triangles Solutions  Power Digit Sum: What is the sum of the digits of the number 2^1  Digit factorials: Find the Sum of All the Curious Numbers  Computing the Longest Recurring Cycle in its Decimal Fraction Pa  How to Use Priority Queue in Java or C++ to Compute Last Stone W  5 Most Important SEO Keyword Metrics, Explained  Why You Should Remove Inactive Subscribers from Your Email List 
评论列表
添加评论