数学题：某工厂有工人1200名，因工作需要，调走男工人的1/8，又新招女工人30名，这时男工人和女工人的人数相等，这个工厂原有男工人多少名？

数学题解答：

用方程解答比较简单，设原有男工人x名。女工人可以表示为（1200-x）。根据“这时男工人和女工人的人数相等”列出方程：

(1 – 1/8)x=1200-x+30

7/8 x = 1230-x

15/8 x = 1230

x = 656

答：原有男工人656名。

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