数学题-这个工厂原有男工人多少名
- 时间:2020-05-12 13:38:15
- 分类:数学世界
- 阅读:144 次
数学题:某工厂有工人1200名,因工作需要,调走男工人的1/8,又新招女工人30名,这时男工人和女工人的人数相等,这个工厂原有男工人多少名?
数学题解答:
用方程解答比较简单,设原有男工人x名。女工人可以表示为(1200-x)。根据“这时男工人和女工人的人数相等”列出方程:
(1 – 1/8)x=1200-x+30
7/8 x = 1230-x
15/8 x = 1230
x = 656
答:原有男工人656名。
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