数学题：正方形ABCD边长8厘米，三角形ABF的面积比三角形CEF的面积大8平方厘米，那么CE长多少厘米?

数学题解答：

当CE=4时，BF=8÷(2+1)×2=16/3，CF=8 – 16/3=8/3。

此时ABF比CEF大：16平方厘米。

当CE=8时，BF=CF=4。

此时ABF比CEF大0平方厘米。

而题中ABF比CEF大8平方厘米，位于16和0的中间处。所以CE的长度应介于4和8之间，并且当CE＝6时，算出ABF的值正好比CEF大8平方厘米。

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